problem: assume you have three points, S, C and O, located some distance from each other:
your task is to find out point T, which is the point that is equally as distant from all three points. how do you go about?
solution: it's not that difficult. first of all, make it a triangle:
next step is to draw a line from each corner of the triangle to the middle of the opposite side:
the intersection is point T.
I was thinking about it last night, and it seems that this is actually the way to go about in doing it: centroid of a triangle
why is this interesting? well, imagine that S = stockholm, C = copenhagen, and O = oslo. T then equals torsvik, which is a small town in sweden, used as a warehouse for transporting between the countries. quite interesting, huh? :)
your task is to find out point T, which is the point that is equally as distant from all three points. how do you go about?
solution: it's not that difficult. first of all, make it a triangle:
next step is to draw a line from each corner of the triangle to the middle of the opposite side:
the intersection is point T.
I was thinking about it last night, and it seems that this is actually the way to go about in doing it: centroid of a triangle
why is this interesting? well, imagine that S = stockholm, C = copenhagen, and O = oslo. T then equals torsvik, which is a small town in sweden, used as a warehouse for transporting between the countries. quite interesting, huh? :)
that is actually interesting... logistics are pretty cool. peace
ReplyDeleteActually this is not the correct. The centroid is not always equidistant from the other points. You need the circumcircle which contains all the vertices of the triangle.
ReplyDeletethere's loads of ways to get the centre of a triangle but i reckon you've got the right one.
ReplyDeleteThis method does not necessarily produce a point that is equidistant from all the vertices of the triangle. You must find the centre of each side of the triangle and then draw a line perpendicular to the side. Do this for each side and the intersection of these lines gives the point that is equidistant from all vertices. I'm an Aerospace Engineering student :)
ReplyDelete